84+2x-6x^2=0

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Solution for 84+2x-6x^2=0 equation:



84+2x-6x^2=0
a = -6; b = 2; c = +84;
Δ = b2-4ac
Δ = 22-4·(-6)·84
Δ = 2020
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2020}=\sqrt{4*505}=\sqrt{4}*\sqrt{505}=2\sqrt{505}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{505}}{2*-6}=\frac{-2-2\sqrt{505}}{-12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{505}}{2*-6}=\frac{-2+2\sqrt{505}}{-12} $

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